Difference between revisions of "Documentation/FAQ/Formula"

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should enter<font color="red">''' x=left lbrace binom -5 3 right none'''</font>.
 
should enter<font color="red">''' x=left lbrace binom -5 3 right none'''</font>.
  
==I enter <font color="red">'''x^*'''</font> to typeset x<SUP>*</SUP>, but get an error message. Why?==
+
==I enter <font color="brown">'''x^*'''</font> to typeset x<SUP>*</SUP>, but get an error message. Why?==
  
The problem is that<font color="red">''' * '''</font>is a binary operator, that is
+
The problem is that<font color="brown">''' * '''</font>is a binary operator, that is
 
there has to be an expression on both sides of the symbol.
 
there has to be an expression on both sides of the symbol.
  
You either have to enter the expression<font color="red">''' x^{{}*{}} '''</font>to avoid the
+
You either have to enter the expression<font color="brown">''' x^{{}*{}} '''</font>to avoid the
error message, or you could type <font color="red">''' x^"*"'''</font> as well, where the quotes
+
error message, or you could type <font color="brown">''' x^"*"'''</font> as well, where the quotes
 
will interprete the asterisk not as a binary operator but as a "standalone" symbol.
 
will interprete the asterisk not as a binary operator but as a "standalone" symbol.
  
 
If you use this construction a lot you might want to define the
 
If you use this construction a lot you might want to define the
 
symbol as a userdefined symbol. See <A HREF="012.html">FAQ #012</A>.
 
symbol as a userdefined symbol. See <A HREF="012.html">FAQ #012</A>.
If you have defined the * as a userdefined symbol, say<font color="red">''' %ast'''</font>,
+
If you have defined the * as a userdefined symbol, say<font color="brown">''' %ast'''</font>,
you can enter<font color="red">''' x^%ast'''</font>.
+
you can enter<font color="brown">''' x^%ast'''</font>.
  
 
This answer applies to a lot of other symbols as well. Some
 
This answer applies to a lot of other symbols as well. Some
 
operators, such as +, are unary, that is there only has to be an
 
operators, such as +, are unary, that is there only has to be an
 
expression to the right of the symbol. To typeset x<SUP>+</SUP> you
 
expression to the right of the symbol. To typeset x<SUP>+</SUP> you
can enter<font color="red">''' x^{+{}}<'''</font> or, of course, <font color="red">'''x^"+"'''</font>.
+
can enter<font color="brown">''' x^{+{}}<'''</font> or, of course, <font color="brown">'''x^"+"'''</font>.
 +
 
 +
==When I enter one of the symbols <font color="brown">'''#'''</font>, <font color="brown">&amp;'''</font>,<font color="brown">|'''</font>, <font color="brown">^'''</font> or <font color="brown">_'''</font> I get an unexpected result or an error message. How can I use these
 +
symbols?==
 +
 
 +
These symbols all have a special meaning in ''Math'':
 +
 
 +
*The symbol<font color="brown">''' # '''</font>is used in stacks and matrices.
 +
*The symbols<font color="brown">''' &amp; '''</font>and<font color="brown">''' | '''</font>are used for logical and and logical or.
 +
*The symbols<font color="brown">''' ^ '''</font>and<font color="brown">''' _ '''</font>are used for
 +
subscripts and superscripts.
 +
 
 +
 
 +
To use them in your formula you can put them in quotation marks,
 +
which means that you insert them as text.
 +
 
 +
If you want to use the symbol &quot;|&quot; you should consider
 +
whether the construction you need is one of the the following:
 +
 
 +
*<font color="brown">'''a divides b '''</font>is used to typeset a| b.
 +
*<font color="brown">'''abs a '''</font>is used to typeset |a|.
 +
 
 +
==When I enter<font color="brown">''' 3xy '''</font>the number 3 comes out in italics. Is this a bug?==
 +
 
 +
Not really. What happens here is, that Math uses multi-letter
 +
variables, which are common in some disciplines, like economy. The
 +
rule is that a variable consists of a sequence of letters, numbers
 +
and dots (the first character can not be a dot).
 +
 
 +
So when you enter 3xy this is considered a variable - and
 +
variables are typeset in italics. The only odd thing here is, that a
 +
variable can start with a number.
 +
 
 +
The correct way to enter the expression if you mean 3 times x
 +
times y is<font color="brown">''' 3 x y '''</font>(with spaces between the characters).

Revision as of 23:30, 13 June 2006

How can I get a left bracket without a right bracket?

Since brackets have a grouping function they must always match and be correctly nested.

To get a single bracket without a matching bracket partner you have to escape the bracket with a backslash. For example to get a "[" without a corresponding "]" you should enter "\[".

Thus to typeset the interval [3;8) you should enter \[3 ";" 8\). The quotation marks around the semicolon ensures that it is not typeset in italic. (You're right, this has nothing to do with brackets!)

For scalable brackets it is essential that left and right matches, since the content that the brackets encloses must be well defined.

In this case you can use the invisible bracket none to get a single bracket. For example to get a scalable "[" without a corresponding "]" you should enter left [ ... right none.

Thus to typeset File:001a.gifyou should enter x=left lbrace binom -5 3 right none.

I enter x^* to typeset x*, but get an error message. Why?

The problem is that * is a binary operator, that is there has to be an expression on both sides of the symbol.

You either have to enter the expression x^{{}*{}} to avoid the error message, or you could type x^"*" as well, where the quotes will interprete the asterisk not as a binary operator but as a "standalone" symbol.

If you use this construction a lot you might want to define the symbol as a userdefined symbol. See <A HREF="012.html">FAQ #012</A>. If you have defined the * as a userdefined symbol, say %ast, you can enter x^%ast.

This answer applies to a lot of other symbols as well. Some operators, such as +, are unary, that is there only has to be an expression to the right of the symbol. To typeset x+ you can enter x^{+{}}< or, of course, x^"+".

==When I enter one of the symbols #, &,|, ^ or _ I get an unexpected result or an error message. How can I use these symbols?==

These symbols all have a special meaning in Math:

  • The symbol # is used in stacks and matrices.
  • The symbols & and | are used for logical and and logical or.
  • The symbols ^ and _ are used for

subscripts and superscripts.


To use them in your formula you can put them in quotation marks, which means that you insert them as text.

If you want to use the symbol "|" you should consider whether the construction you need is one of the the following:

  • a divides b is used to typeset a| b.
  • abs a is used to typeset |a|.

When I enter 3xy the number 3 comes out in italics. Is this a bug?

Not really. What happens here is, that Math uses multi-letter variables, which are common in some disciplines, like economy. The rule is that a variable consists of a sequence of letters, numbers and dots (the first character can not be a dot).

So when you enter 3xy this is considered a variable - and variables are typeset in italics. The only odd thing here is, that a variable can start with a number.

The correct way to enter the expression if you mean 3 times x times y is 3 x y (with spaces between the characters).

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