Difference between revisions of "Documentation/FAQ/Formula/I enter special signs, but get an error message. Why?"
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If you use this construction a lot you might want to define the | If you use this construction a lot you might want to define the | ||
| − | symbol as an user defined symbol. See [[FAQ | + | symbol as an user defined symbol. See [[Documentation/FAQ/Formula#I_need_a_symbol_that_Math_does_not_provide._What_can_I_do.3F|I need a symbol that Math does not provide. What can I do?]]. |
If you have defined the * as an user defined symbol, say<font color="brown">''' %ast'''</font>, | If you have defined the * as an user defined symbol, say<font color="brown">''' %ast'''</font>, | ||
you can enter<font color="brown">''' x^%ast'''</font>. | you can enter<font color="brown">''' x^%ast'''</font>. | ||
Latest revision as of 13:17, 8 October 2021
I enter x^* to typeset x*, but get an error message. Why?
The problem is that * is a binary operator, that is
there has to be an expression on both sides of the symbol.
You either have to enter the expression x^{{}*{}} to avoid the error message, or you could type x^"*" as well, where the quotes will interpret the asterisk not as a binary operator but as a "standalone" symbol.
If you use this construction a lot you might want to define the symbol as an user defined symbol. See I need a symbol that Math does not provide. What can I do?. If you have defined the * as an user defined symbol, say %ast, you can enter x^%ast.
This answer applies to a lot of other symbols as well. Some operators, such as +, are unary, that is there only has to be an expression to the right of the symbol. To typeset x+ you can enter x^{+{}}< or, of course, x^"+".
